Ответ:
[tex]= \frac{(x-3)*(x+3)}{x} *\frac{1}{x-3} -\frac{3}{x+3} +3 = \frac{(x-3)}{x}-\frac{3}{x+3} +3=\frac{(x+3)^{2}-3x+3x*(x+3) }{x*(x+3)} =\frac{(x+3)^{2}-3x+3x^{2} +9) }{x^{2}+3x} =\frac{4x^{2} +12x+9}{x^{2} +3x}[/tex]
Подставляем х = 0.2
[tex]\frac{4*0.2^{2} +12*0.2+9}{0.2^{2} +3*0.2}= \frac{289}{16}[/tex]
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Ответ:
[tex]= \frac{(x-3)*(x+3)}{x} *\frac{1}{x-3} -\frac{3}{x+3} +3 = \frac{(x-3)}{x}-\frac{3}{x+3} +3=\frac{(x+3)^{2}-3x+3x*(x+3) }{x*(x+3)} =\frac{(x+3)^{2}-3x+3x^{2} +9) }{x^{2}+3x} =\frac{4x^{2} +12x+9}{x^{2} +3x}[/tex]
Подставляем х = 0.2
[tex]\frac{4*0.2^{2} +12*0.2+9}{0.2^{2} +3*0.2}= \frac{289}{16}[/tex]