20БАЛЛОВ Найдите корни уравнения: sin((Pi/4)-8x) = минус корень из 3, делённое на 2
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sedinalana
Sin(π/4-8x)=-√3/2 -sin(8x-π/4)=-√3/2 sin(8x-π/4)=√3/2 8x-π/4=π/3+2πk U 8x-π/4=2π/3+2πk 8x=7π/12+2πk U 8x=11π/12+2πk x=7π/96+πk/4 U x=11π/96+πk/4,k∈z
Answers & Comments
-sin(8x-π/4)=-√3/2
sin(8x-π/4)=√3/2
8x-π/4=π/3+2πk U 8x-π/4=2π/3+2πk
8x=7π/12+2πk U 8x=11π/12+2πk
x=7π/96+πk/4 U x=11π/96+πk/4,k∈z
8x-п/4=п/3+2пn
8x-п/4=2п/3+2пn
8x=п/3+п/4+2пn
8x=2п/3+п/4+2пn
8x=7п/12 +2пn
8x=11п/12+2пn
x=7п/96 +пn/4
x=11п/96 +пn/4