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Ответ:

18

Объяснение:

[tex]AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]AB=\sqrt{(5-5)^2+(6+2)^2} =\sqrt{8^2} =8[/tex]

[tex]BC=\sqrt{(2-5)^2+(2-6)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5[/tex]

[tex]AC=\sqrt{(2-5)^2+(2+2)^2}=\sqrt{(-3)^2+4^2}=\sqrt{9+16}=\sqrt{25}=5[/tex]

[tex]P=AB+BC+AC=8+5+5=18[/tex]