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dim06sam
@dim06sam
August 2022
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В треугольнике BCD угол С прямой, sin B=√7/4, BC=3. Найдите BD.
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oganesbagoyan
Verified answer
Дано : ΔBCD ; ∠C =90°;BC =3 ; sinB =(√7)/4.
----
BD -?
cosB =√(1 -sin²B) =√(1 -(√7/4)²) =√(1 -7/16) =√(9/16) =3/4.
cosB =BC /BD⇒BD =BC/cosB =3
/
(3/4)
=4.
ответ: 4.
6 votes
Thanks 8
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Verified answer
Дано : ΔBCD ; ∠C =90°;BC =3 ; sinB =(√7)/4.----
BD -?
cosB =√(1 -sin²B) =√(1 -(√7/4)²) =√(1 -7/16) =√(9/16) =3/4.
cosB =BC /BD⇒BD =BC/cosB =3/ (3/4) =4.
ответ: 4.