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theandrewdid
@theandrewdid
July 2022
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4 Ca + 5 H2SO4 = 4 CaSO4 + H2S + 4 H2O
Ca⁰ -2е = Ca²⁺ ⇒×4 восстановитель
S⁺⁶ + 8 е = S⁻² ⇒×1 окислитель
Почему получается именно так. При подсчете кислорода их разное количество с левой и правой стороны
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seyranov00
Как? 5h2so4 (5×4=20)
4caso4 (4×4=16) + 4h2o (4×1=4)
20=20
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Answers & Comments
4caso4 (4×4=16) + 4h2o (4×1=4)
20=20