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сельджан
@сельджан
September 2021
1
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Найти 1/7 суммы 49 и 56; 1/4 разности 100 и 24; 1/5 произведения 15 и 6; 1/4 частного 72 и 2
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Flash3146
(49+56)×1/7=105×1/7=15
(100-24)×1/4=76×1/4=19
(15×6)×1/5=90×1/5=18
(72÷2)×1/4=36×1/4=9
2 votes
Thanks 3
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Answers & Comments
(100-24)×1/4=76×1/4=19
(15×6)×1/5=90×1/5=18
(72÷2)×1/4=36×1/4=9