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vikulyaabbasova
@vikulyaabbasova
April 2021
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Решите пожалуйста,и упростите в конце получившуюся дробь
k^2/(k+4)^2-16/(-4-k)^2
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Мпрмггнпшоиол
K²/(k+4)²-16/(-(k+4)²)=k²·(-1)/(k+4)²-16/(-(k+4)²=(-((k²)-16)/(-(k+4)²)=(-1(k-4)(k+4)/(k+4)(k+4)=(-1)(k-4)/(k+4)=(-k+4)/(k+4)
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