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anime777999
@anime777999
April 2022
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4. Какой объем при н.у. занимают 9,632 х 1023 молекул брома?
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hentai404
Ответ:дано: N (Br) = 9,632 × 10²³найти: V (Br) = ?решение:V = n × Vmn = N ÷ NAV = N ÷ NA × VmV = 9,632 × 10²³ ÷ 6 × 10²³ × 22,4 = 36 лответ: V (Br) = 36 л.Объяснение:если ещё надо)))
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