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elzamarg
@elzamarg
July 2022
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Помогите решить:
2sin (пи/3 - x/4) = корень из (3)
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0Liza0
2*sin (Пи/3 - x/4) =
√3
sin (
Пи/3 - x/4) =
√3/2
sin t =
√3/2
t1 = Пи/3
t2 = 2Пи/3
Пи/3 - x/4=t
1). Пи/3 - x/4=Пи/3
(4Пи-3x)/12=Пи/3
12Пи=12Пи-9х
9х=0
х=0
х=2Пи
2).
Пи/3 - x/4= 2Пи/3
x/4 = Пи/3 - 2Пи/3
х/4= - Пи/3
x= - 4Пи/3
1 votes
Thanks 2
0Liza0
а, нет, 8Пи
0Liza0
без комм-рия выше
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Answers & Comments
sin (Пи/3 - x/4) = √3/2
sin t = √3/2
t1 = Пи/3
t2 = 2Пи/3
Пи/3 - x/4=t
1). Пи/3 - x/4=Пи/3
(4Пи-3x)/12=Пи/3
12Пи=12Пи-9х
9х=0
х=0
х=2Пи
2).Пи/3 - x/4= 2Пи/3
x/4 = Пи/3 - 2Пи/3
х/4= - Пи/3
x= - 4Пи/3