4. Найдите корни квадратного уравнения 2y² + 3y + 1 = 0. Created by aishaimanberdi2007. algebra-ru

4. Найдите корни квадратного уравнения 2y² + 3y + 1 = 0...

aishaimanberdi2007 @aishaimanberdi2007

July 2022 1 0 Report

4. Найдите корни квадратного уравнения 2y² + 3y + 1 = 0

Answers & Comments

sitnikovaanastasiya1

Ответ:

y=-0,5, y=-1

Объяснение:

$D=b^{2} - 4ac = 3^{2} - 4*2*1 = 9-8 =1\\y_{1} =\frac{-b+\sqrt{D} }{2a} \\=\frac{-3+1}{4} =-0.5\\y_{2} =\frac{-b-\sqrt{D} }{2a} \\=\frac{-3-1}{4} =-1$

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