в треугольнике авс угол с равен 90 sina корень 7/4. Найти sin B
Sin A = CosB
Cos B = 7/4
Sin B = √1-Cos²B = √1-(7/4)²=√1-(49/16)=√-33/16
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Sin A = CosB
Cos B = 7/4
Sin B = √1-Cos²B = √1-(7/4)²=√1-(49/16)=√-33/16