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kill36rus
@kill36rus
September 2021
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№4 нужно срочно решить, помогите!!!
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sedinalana
Verified answer
1-4cos²=sin2x
sin²x+cos²x-4cos²x-2sinxcosx=0/cos²x
tg²x-2tgx-3=0
tgx=a
a²-2a-3=0
a1+a2=2 U a1*a2=-3
a1=-1 ⇒tgx=-1⇒x=-π/4+πn,n∈z
a2=3⇒tgx=3⇒x=arctg3+πk,k∈z
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Answers & Comments
Verified answer
1-4cos²=sin2xsin²x+cos²x-4cos²x-2sinxcosx=0/cos²x
tg²x-2tgx-3=0
tgx=a
a²-2a-3=0
a1+a2=2 U a1*a2=-3
a1=-1 ⇒tgx=-1⇒x=-π/4+πn,n∈z
a2=3⇒tgx=3⇒x=arctg3+πk,k∈z