BJIADA

Verified answer

Ответ смотри во вложении

Arina2806

Verified answer

A) a²-3ab+a-3b=(a²+a)-(3ab+3b)=a(a+1)-3b(a+1)=(a-3b)(a+1)
б) xy-3y²-3y+x=(xy+x)-(3y²+3y)=x(y+1)-3y(y+1)=(x-3y)(y+1)
в) x³-x²y+xy²-y³=(x³-x²y)+(xy²-y³)=x²(x-y)+y²(x-y)=(x²+y²)(x-y)
г) a³-a²+a-1=(a³-a²)+(a-1)=a²(a-1)+1(a-1)=(a²+1)(a-1)