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Angelochek02
@Angelochek02
July 2022
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Найдите сумму первых семи членов геометрической прогрессии. b1 = 1/4, q = 2.
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Ksenia1858
B7=b1*q^7-1
b7=1/4*2^6=1/4*64/1=64/4=16
1 votes
Thanks 3
Angelochek02
спасибо :)
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Answers & Comments
b7=1/4*2^6=1/4*64/1=64/4=16