Ответ:
Объяснение:
а) Mr(H2S) = 1*2 + 32 = 34
W(H) = Ar(H) *n / Mr(H2S) *100% = 1*2 / 34 *100% =6%
б) Mr(NH3) = 14 + 1*3 = 17
W(H) = Ar(H) *n / Mr(NH3) *100% = 1*3 / 17 *100% = 18%
в) Mr(HF) = 1+ 19 = 20
W(H) = Ar(H) *n / Mr(HF) *100% = 1*1 / 20 *100% = 5%
г) Mr(H2O) = 1*2 + 16 = 18
W(H) = Ar(H) *n / Mr(H2O) *100% = 1*2 / 18 *100% =11%
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Ответ:
Объяснение:
а) Mr(H2S) = 1*2 + 32 = 34
W(H) = Ar(H) *n / Mr(H2S) *100% = 1*2 / 34 *100% =6%
б) Mr(NH3) = 14 + 1*3 = 17
W(H) = Ar(H) *n / Mr(NH3) *100% = 1*3 / 17 *100% = 18%
в) Mr(HF) = 1+ 19 = 20
W(H) = Ar(H) *n / Mr(HF) *100% = 1*1 / 20 *100% = 5%
г) Mr(H2O) = 1*2 + 16 = 18
W(H) = Ar(H) *n / Mr(H2O) *100% = 1*2 / 18 *100% =11%