Напишите пожалуйста задачи в Паскале
z1 = 1 - (1/4 * sin(2a) ^ 2 + cos(2a))
z2 = cos(a) ^ 2 + cos(a) ^ 4
z1 = 1 - (1/4 * sin(2a) ^ 2 + cos(2a))
z2 = cos(a) ^ 2 + cos(a) ^ 4
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begin
readln(a);
r:= (1 - (1/4 * sqr(sin(2*a)) + cos(2*a)));
y:= sqr(cos(a)) + sqr(cos(a))*sqr(cos(a));
writeln(r,y);
end.