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magzumturgumbaev866
@magzumturgumbaev866
July 2022
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Найдите суммубесконечно убывающей геометрической прогрессии q) b1=-20 q=1/7 b) b1=16 q=1/4 срооочно
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Thrasher737
Ответ:
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Thrasher737
s=1−qb1=1−71−20=77−1−20=76−20=−20÷76=−20×67=−370=−2331
s = \frac{b1}{1 - q} = \frac{16}{1 - \frac{1}{4} } = \frac{16}{ \frac{4 - 1}{4} } = \frac{16}{ \frac{3}{4} } = 16 \div \frac{3}{4} = 16 \times \frac{4}{3} = \frac{64}{3} = 21 \frac{1}{3}s=1−qb1=1−4116=44−116=4316=16÷43=16×34=364=21
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Ответ:
s = \frac{b1}{1 - q} = \frac{16}{1 - \frac{1}{4} } = \frac{16}{ \frac{4 - 1}{4} } = \frac{16}{ \frac{3}{4} } = 16 \div \frac{3}{4} = 16 \times \frac{4}{3} = \frac{64}{3} = 21 \frac{1}{3}s=1−qb1=1−4116=44−116=4316=16÷43=16×34=364=21