Объяснение:
[tex]2x-3;\ x-4;\ x+2.\\q=\frac{b_2}{b_1}=\frac{b_3}{b_2} \\ \frac{x-4}{2x-3}=\frac{x+2}{x-4} \\ (x-4)^2=(2x-3)(x+2)\\x^2-8x+16=2x^2+x-6\\x^2+9x-22=0\\D=169\ \ \ \ \sqrt{D}=13\\ x_1=-11\ \ \ \ -25;\ -15;\ -9. \ \ \ \ (-25)*(-15)*(-9)=-3375.\\x_2=2\ \ \ \ \ \ \ 1;\ -2;\ \ 4. \ \ \ \ \ \ \ \ 1*(-2)*4=-8.[/tex]
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Объяснение:
[tex]2x-3;\ x-4;\ x+2.\\q=\frac{b_2}{b_1}=\frac{b_3}{b_2} \\ \frac{x-4}{2x-3}=\frac{x+2}{x-4} \\ (x-4)^2=(2x-3)(x+2)\\x^2-8x+16=2x^2+x-6\\x^2+9x-22=0\\D=169\ \ \ \ \sqrt{D}=13\\ x_1=-11\ \ \ \ -25;\ -15;\ -9. \ \ \ \ (-25)*(-15)*(-9)=-3375.\\x_2=2\ \ \ \ \ \ \ 1;\ -2;\ \ 4. \ \ \ \ \ \ \ \ 1*(-2)*4=-8.[/tex]