№1
[tex]1) \;\;y=\frac{x+37}{7x+35}\\7x+35\neq 0= > x\neq -\frac{35}{7}= > x\neq -5.\\D(y)=(-\infty;-5)\cup(-5;+\infty).\\\\2) \;\;y=\sqrt{7-42x} \\7-42x\geq 0= > 42x\leq 7= > x\leq \frac{7}{42} = > x\leq \frac{1}{6} .\\D(y)=(-\infty;\frac{1}{6} ].\\\\3) \;\;y=\frac{5}{x^2-16x+60}\\ x^2-16x+60\neq 0\\T.Vieta:\left \{ {{x_{1}+x_{2}=-b} \atop {x_{1}x_{2}=c}} \right. \left \{ {{x_{1}+x_{2}=16} \atop {x_{1}x_{2}=60}} \;\;]= > x_{1}\neq 6\;;\;\;x_{2}\neq 10.\right. \\D(y)=(-\infty;6)\cup(6;10)\cup(10;+\infty).}[/tex]
[tex]4)\;\;y=\frac{x-1}{2-|x|}\\ 2-|x|\neq 0\\|x|\neq 2 = > x_{1,2} \neq \pm2.\\D(y)=(-\infty;-2)\cup(-2;2)\cup(2;+\infty).[/tex]
№2
[tex]1. \;\;\;D(y)=[-3;+\infty).\\2.\;\;\;E(y)=[-3;+\infty). \\3.\;\;\; [-2;3] \;\;[5;+\infty).\\4.\;\;\;[-3;-2]\;\;[3;5]\\5.\;\;\; -2,5;\;1;\;3,5;\;5,7;\;\;\\6.\;\;\;1)\;y=1;\;2)\;x=-2.\;\;\; \\[/tex]
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
№1
[tex]1) \;\;y=\frac{x+37}{7x+35}\\7x+35\neq 0= > x\neq -\frac{35}{7}= > x\neq -5.\\D(y)=(-\infty;-5)\cup(-5;+\infty).\\\\2) \;\;y=\sqrt{7-42x} \\7-42x\geq 0= > 42x\leq 7= > x\leq \frac{7}{42} = > x\leq \frac{1}{6} .\\D(y)=(-\infty;\frac{1}{6} ].\\\\3) \;\;y=\frac{5}{x^2-16x+60}\\ x^2-16x+60\neq 0\\T.Vieta:\left \{ {{x_{1}+x_{2}=-b} \atop {x_{1}x_{2}=c}} \right. \left \{ {{x_{1}+x_{2}=16} \atop {x_{1}x_{2}=60}} \;\;]= > x_{1}\neq 6\;;\;\;x_{2}\neq 10.\right. \\D(y)=(-\infty;6)\cup(6;10)\cup(10;+\infty).}[/tex]
[tex]4)\;\;y=\frac{x-1}{2-|x|}\\ 2-|x|\neq 0\\|x|\neq 2 = > x_{1,2} \neq \pm2.\\D(y)=(-\infty;-2)\cup(-2;2)\cup(2;+\infty).[/tex]
№2
[tex]1. \;\;\;D(y)=[-3;+\infty).\\2.\;\;\;E(y)=[-3;+\infty). \\3.\;\;\; [-2;3] \;\;[5;+\infty).\\4.\;\;\;[-3;-2]\;\;[3;5]\\5.\;\;\; -2,5;\;1;\;3,5;\;5,7;\;\;\\6.\;\;\;1)\;y=1;\;2)\;x=-2.\;\;\; \\[/tex]