Ответ:
решение смотри на фотографии
[tex]\displaystyle\bf\\1)\\\\2ab-4b+4a^{2} -8a=(2ab-4b)+(4a^{2} -8a)=2b(a-2)+4a(a-2)=\\\\=(a-2)(2b+4a)=2(a-2)(b+2a)\\\\a=0,1 \ \ \ ; \ \ \ b=1\\\\2(a-2)(b+2a)=2\cdot(0,1-2)\cdot(1+2\cdot 0,1)=2\cdot(-1,9)\cdot1,2=-4,56\\\\\\2)\\\\100x^{2} -20x+1=(10x)^{2} -2\cdot 10x\cdot 1+1^{2} =(10x-1)^{2} \\\\x=-0,9\\\\(10x-1)^{2} =\Big[10\cdot\Big(-0,9\Big) -1\Big]^{2} =\Big(-9-1\Big)^{2} =\Big(-10\Big)^{2} =100[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
решение смотри на фотографии
[tex]\displaystyle\bf\\1)\\\\2ab-4b+4a^{2} -8a=(2ab-4b)+(4a^{2} -8a)=2b(a-2)+4a(a-2)=\\\\=(a-2)(2b+4a)=2(a-2)(b+2a)\\\\a=0,1 \ \ \ ; \ \ \ b=1\\\\2(a-2)(b+2a)=2\cdot(0,1-2)\cdot(1+2\cdot 0,1)=2\cdot(-1,9)\cdot1,2=-4,56\\\\\\2)\\\\100x^{2} -20x+1=(10x)^{2} -2\cdot 10x\cdot 1+1^{2} =(10x-1)^{2} \\\\x=-0,9\\\\(10x-1)^{2} =\Big[10\cdot\Big(-0,9\Big) -1\Big]^{2} =\Big(-9-1\Big)^{2} =\Big(-10\Big)^{2} =100[/tex]