[tex](\frac{7}{4} x + \frac{5}{8})12=\frac{17}{2}\\\\ 21x+\frac{15}{2} = \frac{17}{2} \\\\21x = \frac{17}{2} - \frac{15}{2}\\\\21x=1\\x = \frac{1}{21}[/tex]
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[tex](\frac{7}{4} x + \frac{5}{8})12=\frac{17}{2}\\\\ 21x+\frac{15}{2} = \frac{17}{2} \\\\21x = \frac{17}{2} - \frac{15}{2}\\\\21x=1\\x = \frac{1}{21}[/tex]
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