Ответ:
1) b7 = 3√2 × -(√2^(7-1)) = 3√2 × (-√2^6) = 3√2 × (-2^3) = 3√2 × (-8) = -24√2
2) b5 = -2√3 × √3^(5-1) = -2√3 × √3^4 = -2√3 × 3^2 = -18√3
3) b6 = √2 × (-1/√2)^(6-1) = √2 × (-1/√2)^5 = √2 × (-1/√2)^5 = √2 × (-1/√2)^4 × (-1/√2) = √2 × 1/4 × (-1/√2) = √2/4 × (-1/√2) = -1/4
4) b3 = (1 - √2) × (1+√2)^2 = (1-√2) × (1 + 2√2 + 2) =
1-√2 + 2√2 - 4 + 2 - 2√2 = - 1 - √2
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
1) b7 = 3√2 × -(√2^(7-1)) = 3√2 × (-√2^6) = 3√2 × (-2^3) = 3√2 × (-8) = -24√2
2) b5 = -2√3 × √3^(5-1) = -2√3 × √3^4 = -2√3 × 3^2 = -18√3
3) b6 = √2 × (-1/√2)^(6-1) = √2 × (-1/√2)^5 = √2 × (-1/√2)^5 = √2 × (-1/√2)^4 × (-1/√2) = √2 × 1/4 × (-1/√2) = √2/4 × (-1/√2) = -1/4
4) b3 = (1 - √2) × (1+√2)^2 = (1-√2) × (1 + 2√2 + 2) =
1-√2 + 2√2 - 4 + 2 - 2√2 = - 1 - √2