E = 3•10^-20 Дж
P = 400 кПа = 400 000 Па
k = 1,38•10^-23 Дж/К
n - ?
[tex]n = \dfrac{3P}{2E} [/tex]
[tex]n = \dfrac{3 \cdot 400000}{2 \cdot 3 \cdot 10 {}^{ - 20} } = 2 \cdot 10 {}^{25} [/tex]
Ответ: n = 2•10²⁵ м^-3
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Verified answer
E = 3•10^-20 Дж
P = 400 кПа = 400 000 Па
k = 1,38•10^-23 Дж/К
n - ?
[tex]n = \dfrac{3P}{2E} [/tex]
[tex]n = \dfrac{3 \cdot 400000}{2 \cdot 3 \cdot 10 {}^{ - 20} } = 2 \cdot 10 {}^{25} [/tex]
Ответ: n = 2•10²⁵ м^-3