Ответ:
(x,y) = (1,4)
Объяснение:
Спосіб підстановки
1) 3x+y=7
-5x+2y=3
2) y = 7 - 3x
-5x+2y = 3
-5x + 2(7-3x) = 3
-5x + 14 - 6x = 3
-11x + 14 = 3
-11x = -11
x = 1
y = 7 - 3*1
y = 4
3) 3*1 + 4 = 7
-5*1 + 2*4 = 3
4) 7 = 7
3 = 3
Отже (x,y) = (1,4)
[tex]3x + y = 7 \\ - 5x + 2y = 3 \\ \\ y = - 3x + 7 \\ - 5x +2 ( - 3x + 7) = 3 \\ \\ - 5x - 6x + 14 = 3 \\ - 11x = 3 - 14 \\ - 11x = - 11 \\ 11x = 11 \\ x = 11 \div 11 \\ x = 1 \\ \\ y = - 3 \times 1 + 7 = - 3 + 7 = 4[/tex]
Ответ: ( 1 ; 4 )
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Answers & Comments
Ответ:
(x,y) = (1,4)
Объяснение:
Спосіб підстановки
1) 3x+y=7
-5x+2y=3
2) y = 7 - 3x
-5x+2y = 3
-5x + 2(7-3x) = 3
-5x + 14 - 6x = 3
-11x + 14 = 3
-11x = -11
x = 1
y = 7 - 3*1
y = 4
3) 3*1 + 4 = 7
-5*1 + 2*4 = 3
4) 7 = 7
3 = 3
Отже (x,y) = (1,4)
[tex]3x + y = 7 \\ - 5x + 2y = 3 \\ \\ y = - 3x + 7 \\ - 5x +2 ( - 3x + 7) = 3 \\ \\ - 5x - 6x + 14 = 3 \\ - 11x = 3 - 14 \\ - 11x = - 11 \\ 11x = 11 \\ x = 11 \div 11 \\ x = 1 \\ \\ y = - 3 \times 1 + 7 = - 3 + 7 = 4[/tex]
Ответ: ( 1 ; 4 )