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g4merka
@g4merka
July 2022
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Найдите наибольшее значение функции у=24tgx-24x+6п-5 на отрезке [-п/4; п/4]
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sedinalana
Y`=24/cos²x-24=0
cos²x=1
cosx=-1⇒x=π∉[-π/4;π/4]
cosx=1⇒x=0∈[-π/4;π/4]
y(-π/4)=-24+6π+6π-5≈-10
y(0)=0-0+6π-5≈13
y(π/4)=24-6π+6π-5=19 наиб
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Answers & Comments
cos²x=1
cosx=-1⇒x=π∉[-π/4;π/4]
cosx=1⇒x=0∈[-π/4;π/4]
y(-π/4)=-24+6π+6π-5≈-10
y(0)=0-0+6π-5≈13
y(π/4)=24-6π+6π-5=19 наиб