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popovadasha20
@popovadasha20
July 2022
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ПОМОГИТЕ ПОЖАЛУЙСТА!!!
Значение производной функции
f(x)=(-1/2sin^2x)+ln tgx, в точке x0=π/4
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08121981
f(x)=(-1/2sin^2x)+ln tgx
f'(x)=(-1/2)*2sinx*cosx+1/ tgx*1/
cos^2x
f'(x)=(-1/2)*sin2x+cosx/sinx*1/
cos^2x
f'(x)=(-1/2)*sin2x+1/sinx*1/
cosx
f'(x)=(-1/2)*sin2x+2/sin2x
f'(п/4)=(-1/2)*sin(п/2)+2/sin
(п/2)
f'(п/4)=(-1/2)*1+2/1
f'(п/4)=-1/2+2=3/2
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Answers & Comments
f'(x)=(-1/2)*2sinx*cosx+1/ tgx*1/cos^2x
f'(x)=(-1/2)*sin2x+cosx/sinx*1/cos^2x
f'(x)=(-1/2)*sin2x+1/sinx*1/cosx
f'(x)=(-1/2)*sin2x+2/sin2x
f'(п/4)=(-1/2)*sin(п/2)+2/sin(п/2)
f'(п/4)=(-1/2)*1+2/1
f'(п/4)=-1/2+2=3/2