[tex]\displaystyle\bf\\\left \{ {{8x+2y=-6} \atop {-y-x^{2}=6 \ |\cdot 2 }} \right. \\\\\\+\left \{ {{8x+2y=-6} \atop {-2x^{2} -2y=12}} \right.\\-----------\\ -2x^{2} +8x=6\\\\-2x^{2} +8x-6=0\\\\x^{2} -4x+3=0\\\\Teorema \ Vieta:\\\\x_{1} +x_{2} =4\\\\x_{1} \cdot x_{2}=3\\\\x_{1} =1 \ \ ; \ \ x_{2} =3\\\\y=-x^{2} -6\\\\y_{1} =-1^{2} -6=-1-6=-7\\\\y_{2} =-3^{2}-6=-9-6=-15\\\\\\Otvet: \ \Big(1 \ ; \ -7\Big) \ \ , \ \ \Big(3 \ ; \ -15\Big)[/tex]