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Sofa0202
@Sofa0202
August 2022
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Очееень срочноо решите пожалуйста:
а) (2y+1/4)^2
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Junix
(2y+1/4)^2 = 0
4y
²+y+1/16 = 0
64y²+16y+1 = 0
D = 64-64 = 0
y = -8/64 = -1/8
Ответ: - 1/8
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Answers & Comments
4y²+y+1/16 = 0
64y²+16y+1 = 0
D = 64-64 = 0
y = -8/64 = -1/8
Ответ: - 1/8