РЕШИТЕ ДАЮ 50 БАЛЛОВ! ! !(х-3)(х-4)-(х+3)(х+2) при х=-3/4. Created by Sssssid. algebra-ru

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РЕШИТЕ ДАЮ 50 БАЛЛОВ! ! !(х-3)(х-4)-(х+3)(х+2) при х=-3/4

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$x=-\frac{3}{4}\\\\(x-3)(x-4)-(x+3)(x+2)=(x^2-7x+12)-(x^2+5x+6)=\\\\=-12x+6=6(-2x+1)=6(-2\cdot \frac{-3}{4}+1)=6(\frac{3}{2}+1)=\\\\=6\cdot \frac{5}{2}=15$

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