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BravePioneer
@BravePioneer
July 2022
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Cрочно! Представь квадрат двучлена в виде многочлена (1/8y^5-3/4)^2
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Dima1120089
((1/8)y^5 - 3/4)^2 =
((1/8)y^5)^2 - 2*(1/8)y^5*(3/4) + (3/4)^2 =
(1/8)^2*(y^5)^2 - (2*3/8*4)*y^5 + 9/16 =
(1/64)y^10 - (3/16)y^5 + 9/16
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Answers & Comments
((1/8)y^5)^2 - 2*(1/8)y^5*(3/4) + (3/4)^2 =
(1/8)^2*(y^5)^2 - (2*3/8*4)*y^5 + 9/16 =
(1/64)y^10 - (3/16)y^5 + 9/16