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Ahiky
@Ahiky
June 2022
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Помогите пж! (1)x+0,5х=3 (2)х+1/3=12 (3) х+3/4=28 палочки между 1 и 3,и 4 и 3 это обыкновенная дробь
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jekadva
(1)
x+0,5х=3
1,5x=3
x=3:1,5
x=2
(2)
х+1/3=12
3x+1=36
3x=36-1
3x=35
x=35:3
x=11 2/3
(3)
х+3/4=28
4x+3=112
4x=112-3
4x=109
x=109:4
x=27 1/4
1 votes
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Ahiky
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Answers & Comments
x+0,5х=3
1,5x=3
x=3:1,5
x=2
(2)
х+1/3=12
3x+1=36
3x=36-1
3x=35
x=35:3
x=11 2/3
(3)
х+3/4=28
4x+3=112
4x=112-3
4x=109
x=109:4
x=27 1/4