(4*3^22+7*3^21)*57 ---------------------------- (19*27^4)^2. Created by Светлая27. algebra-ru

(4*3^22+7*3^21)*57 ---------------------------- (19*27^4)^2...

Светлая27 @Светлая27

July 2022 1 2 Report

(4*3^22+7*3^21)*57

----------------------------

(19*27^4)^2

Answers & Comments

irkarom $\frac{(4*3^{22}+7*3^{21})*57}{ (19*27^4)^2}=\frac{3^{21}(4*3+7)*57}{ 19*19*27^8}=\frac{3^{21}*19*3}{ 19*(3^3)^8}=\frac{3^{21}*3}{ 3^{24}}=\\
\\
=\frac{3^{22}}{3^{24}}=\frac1{3^{24-22}}=\frac1{3^2}=\frac19$

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