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cucuruzzza
@cucuruzzza
July 2022
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Задание по тригонометрии:
Cos3x<1/4
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СуперМозг12345
1/4 это +-arccos(1/4)+2пn
3x>-arccos(1/4)+2пn и 3x<arccos(1/4)+2пn
x>-1/3arccos1/4)+2пn/3
x<1/3arccos(1/4)+2пn/3
n везде принадлежит Z
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Answers & Comments
3x>-arccos(1/4)+2пn и 3x<arccos(1/4)+2пn
x>-1/3arccos1/4)+2пn/3
x<1/3arccos(1/4)+2пn/3
n везде принадлежит Z