M(Li2O)=7^ * 2 + 16 = 30g / mоl
W(Li) =7^ * 2/30^ * 100\%=46.67\%
W(O) =16/30^ * 100\%=53.37\%
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
M(Li2O)=7^ * 2 + 16 = 30g / mоl
W(Li) =7^ * 2/30^ * 100\%=46.67\%
W(O) =16/30^ * 100\%=53.37\%