[tex]\displaystyle\bf\\\frac{5+\sqrt{5} }{4\sqrt{5} } =\frac{(\sqrt{5} )^{2}+\sqrt{5} }{4\sqrt{5} } =\frac{\sqrt{5}\cdot(\sqrt{5} +1) }{4\sqrt{5} } =\frac{\sqrt{5}+1 }{4}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\\frac{5+\sqrt{5} }{4\sqrt{5} } =\frac{(\sqrt{5} )^{2}+\sqrt{5} }{4\sqrt{5} } =\frac{\sqrt{5}\cdot(\sqrt{5} +1) }{4\sqrt{5} } =\frac{\sqrt{5}+1 }{4}[/tex]