Объяснение:
7. [tex](b-3)(b+3)-(b-2)^2=b^2-9-b^2+4b-4=4b-13[/tex]
8.
[tex](x+6)^2-(x-5)(x+5)=79;\\x^2+12x+36-x^2+25=79;\\12x=79-36-25;\\12x=18;\\x=\frac{18}{12}=\frac{3}{2}=1\frac{1}{2} =1.5[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Объяснение:
7. [tex](b-3)(b+3)-(b-2)^2=b^2-9-b^2+4b-4=4b-13[/tex]
8.
[tex](x+6)^2-(x-5)(x+5)=79;\\x^2+12x+36-x^2+25=79;\\12x=79-36-25;\\12x=18;\\x=\frac{18}{12}=\frac{3}{2}=1\frac{1}{2} =1.5[/tex]