Ответ:
[tex]-\frac{2}{3}[/tex]
Объяснение:
[tex]\frac{ax^2-a^3}{3x^3-3a^2x}=\frac{a(x^2-a^2)}{3x(x^2-a^2)}=\frac{a}{3x}\\\\\frac{\frac{8}{9}}{3\cdot(-\frac{4}{9})}=\frac{\frac{8}{9}}{-\frac{4}{3}}=\frac{8}{9}:(-\frac{4}{3})=\frac{8}{9}\cdot (-\frac{3}{4})=-\frac{2}{3}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
[tex]-\frac{2}{3}[/tex]
Объяснение:
[tex]\frac{ax^2-a^3}{3x^3-3a^2x}=\frac{a(x^2-a^2)}{3x(x^2-a^2)}=\frac{a}{3x}\\\\\frac{\frac{8}{9}}{3\cdot(-\frac{4}{9})}=\frac{\frac{8}{9}}{-\frac{4}{3}}=\frac{8}{9}:(-\frac{4}{3})=\frac{8}{9}\cdot (-\frac{3}{4})=-\frac{2}{3}[/tex]