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Vallery1717
@Vallery1717
July 2022
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Найдите значение выражения 3tg(-pi/6)ctg pi/3 + sin 3pi/2-4cos pi/4
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Санечка69
Verified answer
3tg(-π/6)ctg(π/3) + sin3π/2 - 4cosπ/4 = -3 · 1/√3 · 1/√3 - 1 - 4 · √2/2 = -1 -1 - 2√2 = -2 - 2√2
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Answers & Comments
Verified answer
3tg(-π/6)ctg(π/3) + sin3π/2 - 4cosπ/4 = -3 · 1/√3 · 1/√3 - 1 - 4 · √2/2 = -1 -1 - 2√2 = -2 - 2√2