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alexandra112s
@alexandra112s
June 2022
1
30
Report
√45+√18
________
√5-√2
Освободится от иррациональности в знаменателе дроби
√48-√112
–––---------
√3+√7
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sedinalana
(3√5+3√2)/(√5-√2)=3(√5+√2)²/(√5-√2)(√5+√2)=3(5+2+2√10)/(5-2)=
=3(7+2√10)/3=7+2√10
2
(4√3-4√7)/(√3+√7)=4(√3-√7)²/(√3+√7)(√3-√7)=4(3+7-2√21)/(3-7)=
=4(10-2√21)/(-4)=2√21-10
2 votes
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Answers & Comments
=3(7+2√10)/3=7+2√10
2
(4√3-4√7)/(√3+√7)=4(√3-√7)²/(√3+√7)(√3-√7)=4(3+7-2√21)/(3-7)=
=4(10-2√21)/(-4)=2√21-10