christennn

Ответ:

ACB

AC=?

C²=a²+b²

8²=AC²+6²

AC²=28

AC=

[tex] \sqrt{28} [/tex]

AC=

[tex]2 \sqrt{7} [/tex]

ADC

AD=?

C²=a²+b²

[tex](2 \sqrt{7} ) {}^{2} = ad {}^{2} + ( \sqrt{21} ) {}^{2} \\ ad { }^{2} = - 7 \\ ad = - \sqrt{7} [/tex]