решите уравнение: 4)(1/2-5х)^2+3/4=(5х-4)^2 5)х(х+2)-(х+3)(х-3)=13 6)4х(х-1)-(2х+5)(2х-5)=1. Created by darinka4543. algebra-ru

4=(5х-4)^2 5)х(х+2)-(х+3)(х-3)=13 6)4х(х-1)-(2х+5)(2х-5)=1...

July 2022 1 7 Report

решите уравнение:
4)(1/2-5х)^2+3/4=(5х-4)^2
5)х(х+2)-(х+3)(х-3)=13
6)4х(х-1)-(2х+5)(2х-5)=1

Answers & Comments

zhuldyz16 1) (0,5-5х)2+0,75=(5х-4)2
-24,5х+0,75=-11х
-35,5х=0,75
х=-47,3
2)х2+2х-х2-3х-3х-9=13
-4х=22
-х=5,5
3)4х2-4х-2х2-10х-10х-25-1
2х2+16х-24=0
D=256-192=64
х1=2÷16+8=24÷2=12
х2=2÷16-8=8÷2=4

2 votes Thanks 2

sc11b9fe234ca2b1fb2851a6a78a35392 71370

Answer

darinka4543 July 2022 | 0 Ответы

45h 42 5hh2 h3h 313 64hh 1 2h52h 51

Answer

darinka4543 July 2022 | 0 Ответы

kakoe naimenshee chislo tochek nado udalit na dannom risunke chtoby nikakie tri ib35c4ec398fb97298ce72b06c456808d 83590

Answer

darinka4543 July 2022 | 0 Ответы

na kakoe naibolshee chislo ravnostoronnih treugolnikov mozhno razdelit dannyj ra

Answer

Answers & Comments

sc11b9fe234ca2b1fb2851a6a78a35392 71370

45h 42 5hh2 h3h 313 64hh 1 2h52h 51

kakoe naimenshee chislo tochek nado udalit na dannom risunke chtoby nikakie tri ib35c4ec398fb97298ce72b06c456808d 83590

predstavte v vide mnogochlena 1a2h3 22u 33 3r 3g3 43n 2m3

esli dve storony i mediana provedennaya k odnoj iz etih storon odnogo treugolni

kakoe iz perechislennyh vyskazyvanij vernoe 1 esli odna vysota treugolnika del

na kakoe naibolshee chislo ravnostoronnih treugolnikov mozhno razdelit dannyj ra

рекомендуемые вопросы

Helpful Links

Helpful Social