помогите ! найдите значения многочлена: -2а² b+4b+11a² b при а=-1/3, b=2 3/4. Created by klimenkol21. algebra-ru

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July 2022 1 6 Report

помогите !
найдите значения многочлена:
-2а² b+4b+11a² b
при а=-1/3, b=2 3/4

Answers & Comments

red321 $-2a^2b+4b+11a^2b=9a^2b+4b=b(9a^2+4)=2\frac{3}{4}(9*(-\frac{1}{3})^2+4)=\\=\frac{11}{4}*(9*\frac{1}{9}+4)=\frac{11}{4}*5=\frac{55}{4}=13\frac{3}{4}$

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2x-2...

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klimenkol21 August 2022 | 0 Ответы

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klimenkol21 August 2022 | 0 Ответы

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klimenkol21 August 2022 | 0 Ответы

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klimenkol21 August 2022 | 0 Ответы

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Answer

Answers & Comments

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reshit kvadratnoe uravnenie razlozhiv ego levuyu chast na mnozhiteli 13h5h03fccfdb28b70e12dfa1290621b0bdc92 30754

osnovaniya trapecii 6sm i 9sm vysota 10sm najti rasstoyaniya ot tochki peresecheniya0c50ad104f6e89a3291d70d1402d398b 22936

osnovaniya trapecii 6sm i 9sm vysota 10sm najti rasstoyaniya ot tochki peresecheniyadea6b551016c04c8383f618917441f22 11246

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