решите уравнение
4(х-3)-3(х+2)=-19
2,5(4-2х)-5(1-3х)=5
-5(7-х_-4(х-8)=3
2/3(3х-1)-1/9(9х-2 1/4)=1/4
4(х-3)-3(х+2)=-19
2,5(4-2х)-5(1-3х)=5
-5(7-х_-4(х-8)=3
2/3(3х-1)-1/9(9х-2 1/4)=1/4
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Answers & Comments
4x-12-3x-6=-19
x-18=-19
x=-19+18
x=-1
2) 2,5(4-2x)-5(1-3x)=5
10-5x-5+15x=5
5+10x=5
x=0
3) -5(7-x)-4(x-8)=3
-35+5x-4(-4)=3
-35+5x+16=3
-19+5x=3
5x=22
x=22/5
x=4 2/5
4) 2/3(3x-1)-1/9(9x-2 1/4)=1/4
2x-2/3-1/9(9x-1/2)=1/4
2x-2/3-x+1/18=1/4
x-11/18=1/4
36x-36*11/18=36*1/4
36x-2*11=9
36x-22=9
36x=9+22
36x=31
x=31/36