Ответ:
[tex]( {b}^{5} {)}^{3} \times {(b}^{2} {)}^{7} \div ( {b}^{6} {)}^{4} = {b}^{15} \times {b}^{14} \div {b}^{24} = {b}^{29} \div {b}^{24} = {b}^{5} [/tex]
При b=-2;
[tex] {b}^{5} = - 2 \times ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) = - 32[/tex]
4.9
[tex]( {a}^{2} {)}^{4} \times ( {a}^{3} {)}^{5} \div ( {a}^{3} {)}^{7} = {a}^{2} \\ {a}^{8} \times {a}^{15} \div {a}^{21} = {a}^{2} \\ {a}^{23} \div {a}^{21} = {a }^{2} \\ {a}^{2} = {a}^{2} [/tex]
Тождество доказано!
Подпишись
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Answers & Comments
Ответ:
[tex]( {b}^{5} {)}^{3} \times {(b}^{2} {)}^{7} \div ( {b}^{6} {)}^{4} = {b}^{15} \times {b}^{14} \div {b}^{24} = {b}^{29} \div {b}^{24} = {b}^{5} [/tex]
При b=-2;
[tex] {b}^{5} = - 2 \times ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) = - 32[/tex]
4.9
[tex]( {a}^{2} {)}^{4} \times ( {a}^{3} {)}^{5} \div ( {a}^{3} {)}^{7} = {a}^{2} \\ {a}^{8} \times {a}^{15} \div {a}^{21} = {a}^{2} \\ {a}^{23} \div {a}^{21} = {a }^{2} \\ {a}^{2} = {a}^{2} [/tex]
Тождество доказано!
Подпишись