2 корня, т.к. D>0
[tex] {x}^{1} = \frac{ - b + \sqrt{d} }{2a} \\ {x}^{2} = \frac{ - b - \sqrt{d} }{2a} [/tex]
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2 корня, т.к. D>0
[tex] {x}^{1} = \frac{ - b + \sqrt{d} }{2a} \\ {x}^{2} = \frac{ - b - \sqrt{d} }{2a} [/tex]