под корнем 3 целых 37/196- под корнем 1 целая 15/49 срочноо помогитее. Created by Diana545698. algebra-ru

49 срочноо помогитее...

August 2021 1 11 Report

под корнем 3 целых 37/196- под корнем 1 целая 15/49 срочноо помогитее

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Anastsiia $\sqrt{3 \frac{37}{196} }- \sqrt{1 \frac{15}{49} } = \sqrt{ \frac{3*196+37}{196} }- \sqrt{\frac{49+15}{49} } =\sqrt{ \frac{625}{196} }- \sqrt{\frac{64}{49} } = \\ = \frac{25}{14}- \frac{8}{7}= \frac{25}{14}- \frac{16}{14}= \frac{9}{14}$

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