August 2021 0 22 Report
Вопрос по тригонометрии, проверьте, пожалуйста sin2x/sin(3pi/2-x)=1
2cosxsinx/cosx=1
2sinx=1
sinx=1/2
x=pi/4+pin
На промежутке [3pi/4; 9pi/4]
5pi/4; 9pi/4
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