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heartbreaker
@heartbreaker
July 2022
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(cosx-sinx)(cosx+sinx)=cos3п/4
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nKrynka
Решение
(cosx - sinx)(cosx + sinx) = cos(3π/4)
cos²x - sin²x = - √2/2
cos2x = - √2/2
2x = (+ -)arccos(-√2/2) + 2πk, k∈Z
2x = (+ -)(π - π/4) + 2πk, k∈Z
2x = (+ -)3π/4 + 2πk, k∈Z
x = (+ -)3π/8 + πk, k∈Z
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Answers & Comments
(cosx - sinx)(cosx + sinx) = cos(3π/4)
cos²x - sin²x = - √2/2
cos2x = - √2/2
2x = (+ -)arccos(-√2/2) + 2πk, k∈Z
2x = (+ -)(π - π/4) + 2πk, k∈Z
2x = (+ -)3π/4 + 2πk, k∈Z
x = (+ -)3π/8 + πk, k∈Z