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kdickareva
@kdickareva
August 2022
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для функции f(x)=5cos x вычислите f'(-3π/4)
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hlopushinairina
F(x)=5cosx;
f¹(x)=5·(-sinx)=-5sinx;
f¹(-3π/4)=-5·sin(-3π/4)=-5·(-sin(3π/4)=5·sin(π-π/4)=5·sinπ/4=5·√2/2;
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Answers & Comments
f¹(x)=5·(-sinx)=-5sinx;
f¹(-3π/4)=-5·sin(-3π/4)=-5·(-sin(3π/4)=5·sin(π-π/4)=5·sinπ/4=5·√2/2;