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April 2021 1 15 Report

Помогите решить
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Мпрмггнпшоиол Найти значение функции y = √4-4x+x² + ⁴√(x²-6x+9)² в точке x = √5:
y = √4-4x+x² + ⁴√(x²-6x+9)² = √4-4·√5+(√5)² + ⁴√((√5)²-6·√5+9)² = √4-√4²·5+(√5·√5) + ⁴√((√5 · √5)-√6²·5+9)² = √4-√16·5+√5·5 + ⁴√((√5·5)-√36·5+9)² = √4-√80+√25 + ⁴√(√25-√36+9)² = √4+√(5)²-8,94427191 + ⁴√(5-6+9)² = √4+5-8,94427191 + ⁴√(8)² = √0,05572809 + 8∧2/4 = 0,23606797749 + 8∧1/2 = √8 + + 0,23606797749 = 0,23606797749 + 2,82842712475 = 0,3261 + 2,8284 = 3,1545 = 3,2

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